COUNT() 函数
发表于 2018-3-7 10:47:32 | 分类于 SQL |
COUNT() 函数
COUNT()
函数返回匹配指定条件的行数。
COUNT(column_name) 语法
函数返回指定列的值的数目(NULL 不计入):
SELECT COUNT(column_name) FROM table_name;
COUNT(*) 语法
COUNT(*) 函数返回表中的记录数:
SELECT COUNT(*) FROM table_name;
COUNT(DISTINCT column_name) 语法
返回指定列的不同值的数目:
SELECT COUNT(DISTINCT column_name) FROM table_name;
注释 : COUNT(DISTINCT)
适用于 ORACLE 和 Microsoft SQL Server,但是无法用于 Microsoft Access。
示例
"access_log" :
+-----+---------+-------+------------+
| aid | site_id | count | date |
+-----+---------+-------+------------+
| 1 | 1 | 45 | 2016-05-10 |
| 2 | 3 | 100 | 2016-05-13 |
| 3 | 1 | 230 | 2016-05-14 |
| 4 | 2 | 10 | 2016-05-14 |
| 5 | 5 | 205 | 2016-05-14 |
| 6 | 4 | 13 | 2016-05-15 |
| 7 | 3 | 220 | 2016-05-15 |
| 8 | 5 | 545 | 2016-05-16 |
| 9 | 3 | 201 | 2016-05-17 |
+-----+---------+-------+------------+
COUNT(column_name) 实例
计算 "access_log" 表中 "site_id"=3 的总访问量:
SELECT COUNT(count) AS nums FROM access_log
WHERE site_id=3;
COUNT(*) 实例
计算 "access_log" 表中总记录数:
SELECT COUNT(*) AS nums FROM access_log;
输出结果:
mysql> SELECT COUNT(*) AS nums FROM access_log;
+-------+
| nums |
+-------+
| 9 |
+-------+
COUNT(DISTINCT column_name) 实例
计算 "access_log" 表中不同 site_id 的记录数:
SELECT COUNT(DISTINCT site_id) AS nums FROM access_log;
输出结果:
mysql> SELECT COUNT(DISTINCT site_id) AS nums FROM access_log;
+-------+
| nums |
+-------+
| 5 |
+-------+
练习
-- 查询所有记录的条数
select count(*) from access_log;
-- 查询 websites 表中 alexa 列中不为空的记录的条数
select count(alexa) from websites;
-- 查询 websites 表中 country 列中不重复的记录条数
select count(distinct country) from websites;